Hydraulic Power Formula:
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Hydraulic pump motor power represents the mechanical power required to drive a hydraulic pump, calculated from flow rate and pressure. It determines the size of motor needed for hydraulic systems in industrial machinery, construction equipment, and automotive applications.
The calculator uses the hydraulic power formula:
Where:
Explanation: This formula converts hydraulic power (flow × pressure) to mechanical horsepower, accounting for unit conversions between imperial measurements.
Details: Accurate hydraulic power calculation is essential for proper motor selection, system efficiency optimization, preventing motor overload, and ensuring reliable hydraulic system operation in industrial applications.
Tips: Enter flow rate in GPM and pressure in PSI. Values must be positive numbers. For system design, consider adding a safety factor of 10-20% to the calculated horsepower.
Q1: What is the conversion constant 0.000583 derived from?
A: It combines unit conversions: 1 HP = 550 ft-lb/sec, 1 GPM = 0.002228 ft³/sec, and pressure conversion factors.
Q2: How does efficiency affect motor selection?
A: The calculated HP is theoretical. Actual motor size should account for pump efficiency (typically 80-95%) and system losses.
Q3: Can this formula be used for metric units?
A: No, this formula is for imperial units. For metric: Power (kW) = (Flow × Pressure) / 600, where flow in L/min and pressure in bar.
Q4: What are typical HP ranges for hydraulic systems?
A: Small systems: 1-10 HP, Medium industrial: 10-100 HP, Large machinery: 100-500+ HP depending on application.
Q5: Why is proper motor sizing important?
A: Undersized motors overload and fail, while oversized motors increase cost, reduce efficiency, and waste energy.